if y=e^x log x find dy/dx
Answers
Answered by
0
Answer:
apply product rule
e^x×1/x+ logx×e^x
Answered by
3
Step-by-step explanation:
given y= e*x .logx
dy/dx=(e*x)'.logx+ e*x(logx)'
[u.v method]
dy/dx=e*x .log x+e*x(1/x)
= e*x(logx+1/x)
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