Question

if y=tan(3x-2) then find dy/dx​

Answer 1

Answer:

$\frac{dy}{dx} = 3{sec}^{2} (3x - 2)$

step by step explaination

$= > y=tan(3x-2) \\ \\ = > \frac{dy}{dx} = \frac{d}{dx}tan(3x-2) \\ \\ = > \frac{dy}{dx} = {sec}^{2} (3x - 2)\frac{d}{dx}(3x - 2) \\ \\ = > \frac{dy}{dx} = {sec}^{2} (3x - 2).3 \\ \\ = > \frac{dy}{dx} = 3{sec}^{2} (3x - 2)$