Question

If you pitch a baseball with twice the kinetic energy you gave it in the previous pitch, the magnitude of its
momentum is
(A) the same (B) 1.41 times as much (C) doubled
(D) 4 times as much​

Answer 1

Answer:

c) doubled

Explanation:

we know the relationship between kinetic energy and momentum :

K E = P / 2M

where KE is kinetic energy and P is momentum

M is mass

KE /2 KE = P / P' ( since both 2M are cancelled)

P' = 2P

I HOPE THIS WILL HELP YOU AND MARK THE IT AS BRAINLIEST ANSWER

Answer 2

Answer:

initial k.e be 1/2 *( m v^2) ..where v is initial velocity...so we have final k.e as 2 times intial one..

so final k.e is 1/2 * (mx^2 )where x is the final velocity

dividing final by intial one we get

x^2/v^2 = 2

x/v= root 2

x= root 2 *v

final momentum is m(root2*v) =1.41 times intial one