If z = r( cos theta + i sin theta ) , then value of z/z + z/z is
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Given : z = r( cosθ + i sin θ )
To Find :
Solution:
z = r( cosθ + i sin θ )
= r( cosθ - i sin θ )
= r( cosθ + i sin θ ) /r ( cosθ - i sin θ ) + r( cosθ - i sin θ ) /r( cosθ + i sin θ )
= ( cosθ + i sin θ ) / ( cosθ - i sin θ ) + ( cosθ - i sin θ ) / ( cosθ + i sin θ )
= ( ( cosθ + i sin θ )² + ( cosθ - i sin θ )²) /(cos²θ - i² sin² θ)
= ( 2( cos²θ + i² sin² θ )) /(cos²θ - i² sin² θ)
i² = - 1
= ( 2( cos²θ - sin² θ )) /(cos²θ + sin² θ)
cos²θ + sin² θ = 1
cos²θ - sin² θ = cos2θ
= 2 cos2θ
= 2 cos2θ
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