If z = x + iy then solve the equation iz + 2i + 1 = 0 ?
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Ramuchaudhary:
Answer is x = -2 , y = 1
Answered by
1
given,
z=x+iy
iz+2i+1=0
=>i(x+iy)+2i+1=0
=>ix+(i^2)+2i+1=0
=>i(x+2)-1+1=0
=>I(x+2)=0
=>x+2=0
=>x=-2
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z=x+iy
iz+2i+1=0
=>i(x+iy)+2i+1=0
=>ix+(i^2)+2i+1=0
=>i(x+2)-1+1=0
=>I(x+2)=0
=>x+2=0
=>x=-2
HOPE THIS HELPS YOU
PLEASE MARK AS BRAINLIEST
answer is x = - 2 , y = 1
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