Question

if ZIP=198 and ZAP=246 then how will you code VIP

Answer 1

Hey There!

The logic of the series is (1st - 2nd + 3rd term) * 6.
Here, A = 1, B = 2, C = 3, .........., Z = 26.

So,

ZIP = (26 - 9 + 16) * 6 = 33 *6 = 198.
ZAP = (26 - 1 + 16) * 6 = 41 * 6 = 246

So,
VIP = (22 - 9 + 16) * 6 = 29 * 6 = 174.

Therefore, VIP= 174

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Answer 2

VIP will coded as 174.

Explanation:

We have,

ZIP = 198 and ZAP = 246

To find, the code of VIP = ?

Put A = 1, B = 2, C = 3, ..........,Y = 25, Z = 26

The pattern follow:

(1st letter of position - 2nd letter of position + 3rd letter of position) × 6

ZIP ⇒ Z = 26, I = 9 and P = 16

ZIP = (26 - 9 + 16) × 6 = 33 × 6 = 198

ZAP ⇒ Z = 26, A = 1 and P = 16

ZAP = (26 - 1 + 16) × 6 = 41 × 6 = 246

Similarly,

VIP ⇒ V = 22, I = 9 and P = 16

VIP = (22 - 9 + 16) × 6 = 29 × 6 = 174

Hence, VIP will coded as 174.