If2a+3b=7 and ab=2,find4a2+9b2.
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2a + 3b = 7
( 2a + 3b )^2 = (7)^2
4a ^2 + 9b ^2 + 12ab = 49
4a^2 + 9 b ^2 + 12*2 = 49
4a ^2 + 9b^2 =49 - 24
4a^2 + 9b ^ 2 = 25 ans .
if you have any problem regarding this solution please comment!
( 2a + 3b )^2 = (7)^2
4a ^2 + 9b ^2 + 12ab = 49
4a^2 + 9 b ^2 + 12*2 = 49
4a ^2 + 9b^2 =49 - 24
4a^2 + 9b ^ 2 = 25 ans .
if you have any problem regarding this solution please comment!
Answered by
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dont know the answer sorry
yuvrajrathore:
wait i am sending
2a + 3b = 7
( 2a + 3b )^2 = (7)^2
4a ^2 + 9b ^2 + 12ab = 49
4a^2 + 9 b ^2 + 12*2 = 49
4a ^2 + 9b^2 =49 - 24
4a^2 + 9b ^ 2 = 25 ans .
( 2a + 3b )^2 = (7)^2
4a ^2 + 9b ^2 + 12ab = 49
4a^2 + 9 b ^2 + 12*2 = 49
4a ^2 + 9b^2 =49 - 24
4a^2 + 9b ^ 2 = 25 ans .
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