Question

maths help me out question no 1and2

Answer 1

(1):

$\frac{8x - 3}{3x} = 2 \\ \\ \frac{8x - 3}{3x} = \frac{2}{1} \\ \\ (8x - 3)1 = 2(3x) \\ \\ 8x - 3 = 6x \\ \\ 8x - 6x = 3 \\ \\ 2x = 3 \\ \\ x = \frac{3}{2}$


(2):

$\frac{9x}{7 - 6x} = 15 \\ \\ \frac{9x}{7 - 6x} = \frac{15}{1} \\ \\ 9x(1) = 15(7 - 6x) \\ \\ 9x = 105 - 90x \\ \\ 9x + 90x = 105 \\ \\ 99x = 105 \\ \\ x = \frac{105}{99} = \frac{35}{33}$




I hope this will help you


(-;

Answer 2

HEYA USER!!! HERE IS UR ANS

1) 8x-3/3x=2
=> 8x-3=2×3x
=> 8x-3=6x
=> 8x-6x=3
=> 2x=3
=> x=3/2

2) 9x/7-6x=15
=> 9x/7-6x=15/1
=> 1(9x)=15(7-6x)
=> 9x= 105-90x
=> 9x+90x=105
=> 99x=105
=> x=105/99
=> x=35/33

HOPE IT WILL HELPS UH!!✌✌