Question

ii) If each side of a cube is increased by 50% then the surface area of the cube
increases by​

Answer 1

Step-by-step explanation:

let the side of the cube be a

tsa-6a^2

new tsa-6(a+50%ofa)^2

=6(a+1/2a)^2

=6(3/2a)^2

=6×9/4a^2

=27/2a^2 new tsa

surface area increases by=

27/2a^2-6a^2

(27-12)a^2/2

15/2a^2

percentage

(15/2a^2)/6a^2×100

125%

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