Question

(ii) (x + y) (8x - y); x = 1, y = 0
(iii) (p2 + 3q) (p2 – 3q); p =-1, q = 2

please give answer​

Answer 1

Step-by-step explanation:

(i)(1+0)(8(1)-0)

=1*8

=8

one more method is

=x (8x-y)+y(8x-y)

=8x^2 - xy + 8xy - y^2

=8*1 - 0 + 0 + 0

=8

(ii) using ( a+b ) ( a-b ) =

=a^2 - b^2

=(1)^2 - 2^2

=1 -4

=-3

plz thanks me ...

Answer 2

Answer:

$Use the shell method.</p><p></p><p></p><p></p><p>Take a vertical cross section of the region. The width of the cross section is dx, and the height is 8x3.</p><p></p><p></p><p></p><p>Rotate the cross section about the line x = 2. The height of the shell is 8x3, the radius is 2 - x, and the thickness is dx. . </p><p></p><p></p><p></p><p>Volume of shell = 2π(2-x)(8x3)dx = 2π(16x3 - 8x4)dx</p><p></p><p></p><p></p><p>Volume of solid = 2π∫(from 0 to 1)[16x3 - 8x4]dx = 2π(4x4 - (8/5)x5)(from 0 to 1) = 24π/5$

$ANSWER</p><p>Let f(x)=3x </p><p>−</p><p> 5x−2 roots p,qp+q=5/3pq=−2/3</p><p>Equation whose roots are 3p−2q & 3q−2p</p><p>x </p><p>2</p><p> −(3p−2q+3q−2p)x+(3p−2q)(3q−2p)=0</p><p>x </p><p>2</p><p> −(p+q)x+(9pq−6p </p><p>2</p><p> −6p </p><p>2</p><p> −6q </p><p>2</p><p> +4pq)=0</p><p>x </p><p>2</p><p> −(p+q)x+(13pq−6(p </p><p>2</p><p> +q </p><p>2</p><p> ))=0</p><p>x </p><p>2</p><p> −(p+q)x+(13pq∗6((p </p><p>2</p><p> +q </p><p>2</p><p> )−2pq))=0</p><p>x </p><p>2</p><p> −(p+q)x+(13pq−6(p+a) </p><p>2</p><p> +12pq)=0</p><p>x </p><p>2</p><p> −(p+a)x+(25pq−6(p+q) </p><p>2</p><p> )=0</p><p>x </p><p>2</p><p> − </p><p>3</p><p>5x</p><p> </p><p> +(25( </p><p>3</p><p>−2</p><p> </p><p> −6( </p><p>3</p><p>5</p><p> </p><p> ) </p><p>2</p><p> ))=0</p><p>x </p><p>2</p><p> − </p><p>3</p><p>5x</p><p> </p><p> +(− </p><p>3</p><p>50</p><p> </p><p> − </p><p>9</p><p>150</p><p> </p><p> )=0</p><p>x </p><p>2</p><p> − </p><p>3</p><p>5x</p><p> </p><p> +(− </p><p>3</p><p>50</p><p> </p><p> − </p><p>3</p><p>50</p><p> </p><p> )=0</p><p>3x </p><p>2</p><p> −5x−100=0$