Question

Illustration 12:
Find the product of 671 992
Solutson:
The complements are 329 and 008 and the product of these two numbers is 2632.
There is only three space for 632 and so 2 must be carried.
For cross subtraction we have
671 - 8 + 2 = 665.
671-329
992-008
665/632
The product is 665632.
how it's possible
send the answer and explanation
get 25 points​

Answer 1

Answer:

Answer:

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♡AnSwEr♡

Explanation:

Let mass of circular disc is M and radius R.

Given, Moment of Inertia (MOI) about one of its diameter = l, ⇒ MR^2/4 = l ⇒MR^2 =4l .....1

MOI about an axis passing through the centre of the disc= MR^ 2/2

Using parallel theorem of MOI, I = I cm +mx^ 2

, Where I cm is MOI of centre of mass and x is the distance between centre of mass and axis of rotation.

MOI about an axis tangent to disc and perpendicular to its plane= MR ^2/2 +MR ^2 = 3/2 MR ^2 =6l (Using equation 1, MR ^2 =4l)