Imagine that an object moving with a uniform velocity of 7ms doesn't change his velocity for the next 10 sec.what will be his accleration during 10 sec
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Answered by
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v = u+at
Here, u=0; v=7m/s; t=10secs
By substituting we get,
7 = 10a
a = 7/10
a = 0.7m/s²
Here, u=0; v=7m/s; t=10secs
By substituting we get,
7 = 10a
a = 7/10
a = 0.7m/s²
nagash2007:
Thanks a billion i gotta test
Answered by
0
[~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~]
[Hello ]
[®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®]
Topic:- FORCE
Here...
We know that;
v=u+at
===========================
We have;
u=0
Time=10 sec
=====================
Now.. Putting the value of Required terms;
V=u+at
7=0+a(10)
7=a10
a=7/10
a=0.7m/s
====================
Answer:- 0.7m/s
[Hello ]
[®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®®]
Topic:- FORCE
Here...
We know that;
v=u+at
===========================
We have;
u=0
Time=10 sec
=====================
Now.. Putting the value of Required terms;
V=u+at
7=0+a(10)
7=a10
a=7/10
a=0.7m/s
====================
Answer:- 0.7m/s
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