Chemistry, asked by sehersheikh8084, 1 year ago

In 1kg of mixture of sand and iron,20% is iron. How much sand should be added to that so the proportion of iron become 10% select one: a. 1.8gms b. 800gms c. 200gms d. 1kg

Answers

Answered by som898481
1

Iron % per 1 kg mixture = 20%

Required % = 10%

20/10 = 2

2*1 kg = 2 kg

Final weight - Initial weight = 1kg

so 1 kg more sand is require.


Similar questions