What is the probability that 2 cards belong to the same suit?
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If the suit is fixed ahead of time, i.e. you need the probability to draw 2 hearts, not any 2 of the same suit, then first probability is 13/52 and second is 12/51, so indeed the total is
13/52×12/51=3/51=1/17≈5.88%
13/52×12/51=3/51=1/17≈5.88%
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