In a 12 volt battery, it is connected across an unknown resistor, their is a current of 2.5 miliampere in the circuit. find the value of the resistance of the resistor
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We have potential difference (V) = 12V
Electric current (I)=2.5 mA= 2.4×10-3
According to Ohm’s Law (V) = IR
Or R = V/I
R = 12/2.5 *10^-3
R =4.8*10^3 ohm
Electric current (I)=2.5 mA= 2.4×10-3
According to Ohm’s Law (V) = IR
Or R = V/I
R = 12/2.5 *10^-3
R =4.8*10^3 ohm
Answered by
1
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According to Ohm’s law,
V = IR
=v/I
Here, V = 12 V and I = 2.5 mA = 0.0025 A Therefore,
=12/ 0.0025 = 4800 Ω = 4.8 kΩ
I hope, this will help you___❤❤
Thank you
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