in a 2 digit number the digit in unit place is twice of the digit in tenth place. If the digit are inversed the new number is 27 mire than the given number. Find the number
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Let the digit in the units place be x
Hence the digit in the tens place is (x + 5)
The original number = 10(x + 5) + x = 11x + 50
Number formed by reversing the digits = 10x + (x + 5) = 11x + 5
Given that (11x + 50) + (11x + 5) = 99
⇒ 22x + 55 = 99
⇒ 22x = 99 55 = 44
⇒ x = 2
Original number = 11x + 50 = 11(2) + 50 = 72
Hence the original number is 72.
can this is right anser
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