Question

The volume of the conical tent is 1232m cube and the area of the base is 154m squre.calculate the radius of the floor,height of the tent,length of the canvas required to cover this conical tent if its width is 2m

Answer 1

$\frac{1}{3} \pi {r}^{2} h = 1232 {m}^{3} \\ \pi {r}^{2} = 154 {m}^{2} \\ \frac{22}{7} \times {r}^{2} = 154 \\ {r}^{2} = \frac{154 \times 7}{22} = 7 \times 7 \\ r = 7m \\ \frac{1}{3} \times 154 \times h = 1232 \\ h = \frac{1232 \times 3}{154} \\ h = 24m \\ {l}^{2} = {r}^{2} + {h}^{2} = {7}^{2} + {24}^{2} = 49 + 576 = 625 \\ l = 25m \\ area \: of \: canvas = \pi \: rl \\ length \times 2m = \frac{22}{7} \times 7 \times 25 \\ length = \frac{22 \times 7 \times 25}{2 \times 7} = 11 \times 25 = 275m$