in a 2-digitnumber,the face value of the digit at the tens place is four times that of the digit at one's place.if 54 is subracted from the number ,the digits are reversed.find the number. (after finding the number check that LHS=RHS)
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Answered by
3
Let number be 10x +y
According to first condition
x= 4y
According to second condition
10x+y-54 = 10y +x
9x-9y=54
x-y=6
4y-y=6
y=2
thus x= 8
So the number is 8(10)+2
which is 82
L.H.S= 10x+y-54 = 82-54=28
R.H.S = 10y+x = 2(10) +8 =28
Hence Verified
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According to first condition
x= 4y
According to second condition
10x+y-54 = 10y +x
9x-9y=54
x-y=6
4y-y=6
y=2
thus x= 8
So the number is 8(10)+2
which is 82
L.H.S= 10x+y-54 = 82-54=28
R.H.S = 10y+x = 2(10) +8 =28
Hence Verified
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Follow for more doubt solving
Manekdev:
Condition dekh
what is mean by face value
Face value means the digit on the tens place
unit digit is only xaccording toquestion
it mean value of digit
in a number
For 82 the face value of tens place is 8 and that of units place is 2
how that 4y-ycoming
substitution
by first condition
Answered by
0
As they have said that face value of tens place is 4 times the ones place. the combinations may be 41 and 82 .
And they have even said that when 54 is subtracted from that no. then the digits get reversed. so the no. must be greater than 54.
hence, the no. is 82.
LHS = RHS
82 - 54 = 28
And they have even said that when 54 is subtracted from that no. then the digits get reversed. so the no. must be greater than 54.
hence, the no. is 82.
LHS = RHS
82 - 54 = 28
yes Ian satisfied with your answer
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