In a 3 digit number ,unit's digit,ten's digit,hundred's digit are in the ratio 1:2:3.if the difference of original number and then number obtained by reversing the digit is 594 find the number
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[(300+20+1) - (100+20+3)] × X =594
=> 198X = 594
=> X = 594÷198 = 3
Required no. = (300+20+1)×3 =321×3 = 963
Hope it will help you
=> 198X = 594
=> X = 594÷198 = 3
Required no. = (300+20+1)×3 =321×3 = 963
Hope it will help you
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