Sargam thinks of a number and add 7/2 to it. He multiples the result by 5. The result now obtained is 4 times the same number he thought of. What is the number
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Let the number that Sangram thinks be x.
➡ He adds (7/2) to that number.
=> x + (7/2) = ( 2x + 7)/2
➡ Then, he multiplies the result by 5.
=> 5 * ( 2x+7)/2 = ( 10x + 35)/2
➡ Now, the result is four times the number.
A/q,
4x = (10x + 35)/2
➡10x + 35 = 8x
➡ 10x - 8x = -35
➡ 2x = -35
➡ x = (-35)/2
Answer :- The number which Sangram thinks is (-35/2).
Hope it will help you !!!
Let the number that Sangram thinks be x.
➡ He adds (7/2) to that number.
=> x + (7/2) = ( 2x + 7)/2
➡ Then, he multiplies the result by 5.
=> 5 * ( 2x+7)/2 = ( 10x + 35)/2
➡ Now, the result is four times the number.
A/q,
4x = (10x + 35)/2
➡10x + 35 = 8x
➡ 10x - 8x = -35
➡ 2x = -35
➡ x = (-35)/2
Answer :- The number which Sangram thinks is (-35/2).
Hope it will help you !!!
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