Question

In a 4-bit Johnson counter sequence, there are a total of how many states or bit patterns?

1

3

4

8​

Answer 1

Explanation:

Total Number of Unused states = 16 – 8 = 8.

Answer 2

$\huge{\mathcal{\purple{A}\green{N}\pink{S}\blue{W}\purple{E}\green{R}\pink{!}}}!$

• 8 is the answer
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