In a △ABC, AB = AC. If the bisector of ∠B and ∠C meet AC and AB at point D and E respectively, show that: △DBC ≅ △ECB
Answers
Step-by-step explanation:
ANSWER:-
Given:-
- A triangle ABC
- AB = AC
The diagram will be like the ATTACHMENT provided.
How?
We know that:-
- AN and AC are same.
- If the 2 sides of Triangle are same, so are the corresponding sides.
So, we can say
So, let's put it right !
In Triangle ECB and DBC,
Angle ABC = Angle DCB
BC = BC ( Common)
Angle ECB = Angle DBC.
By ASA congruence,
△DBC ≅ △ECB
Hence Proved!
★ QUESTION :
In A triangle ABC, AB = AC. If the bisector of ∠B and ∠C meets AC and AB at the point D and E respectively, show that ∆DBC ≅ ∆ECB
GIVEN :
- There is a provided ∆ABC
- In which AB = AC (From the given ∆ABC)
TO FIND :
- To prove (Show) that ∆DBC ≅ ∆ECB
STEP -BY-STEP EXPLAINATION :
➠ ∆ABC (given triangle in the figure)
➠ AB = AC
➠ ∠B = ∠C
Now, we will have to prove (show) that ∆DBC ≅ ∆ECB, so let us prove here :
⟹ AB = AC
⟹ BC = BC (common)
⟹ ∠EBC = ∠DBC
Now, let us see that, from which congruency criteria, will ∆DBC ≅ ∆ECB be Proved :
ㅤㅤㅤㅤㅤㅤ➠ ∆DBC ≅ ∆ECB
This ∆DBC will be congruent to ∆ECB from A-S-A congruence congruence criteria.
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⭐ ADDITIONAL INFORMATION ⭐
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♦ According to congruency if we will proof then, R.H.S will be defined as Right angle hypotenuse side.
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♦ According to congruence if we will prove here then, L.H.S will be defined here as Left hand side.
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♦ A-S-A : This is a congruence criteria, which is used in geometrical parts of mathematics to show its congruence criteria. This A-S-A will be defined as Angle - side - Angle.
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♦ S-S-S : This is a congruence criteria, which is used in geometrical parts of mathematics to show its congruence criteria, there are different types of congruence criteria. This S-S-S will be defined here as Side-side-side.
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♦ S-A-S : This is a category of congruence criteria, which is used for triangles to show that, from which congruence criteria, that triangle is congruent. This S-A-S will be defined as side-angle-side.
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