In a ΔABC, if 2∠A = 3∠B = 6∠C. Determine ∠A, ∠B and ∠C?
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Degree is not written in calculation.
Answer:
90° , 60° and 30°
Step-by-step explanation:
Here,
2∠A = 3∠B = 6∠C.
⇒ 2∠A = 3∠B ; 2∠A = 6∠C
⇒ (2/3)∠A = B ; (2/6)∠A = ∠C
⇒ (2/3)∠A = B ; (1/3)∠A = ∠C
In a triangle :
Sum of all angles is 180°
⇒ ∠A + ∠B + ∠C = 180°
⇒ ∠A + (2/3)∠A + (1/3)∠A = 180
⇒ ( 3∠A + 2∠A +∠A ) / 3 = 180
⇒ 6∠A / 3 = 180
⇒ 2∠A = 180
⇒ ∠A = 180 / 2 = 90
Hence,
∠B = (2/3)∠A
= (2/3) 90
= 60
∠C = (1/3)∠A
= (1/3)90
= 30
Hence the required angles are 90° , 60° and 30°.
∠A = 90° ; ∠B = 60° ; ∠C = 30°
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