Question

in a ∆Abc is isosceles with AB = AC, Angle ABC 50° find angle a, angle acb,angle acd

Answer 1

given AB=AC
so b=c
so angle acb = 50
also ACD=50
in triangle ABC,
a+b+c = 180
so a+100=180
a=180-100
a=80

Answer 2

the value of angle ACB = 50 degree
the value of angle BAC = 80 degree