in a∆ABC right angled at B, if AB=4&BC=3, find all the six trignometic ratios of ∆A
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First let find Hypotenus
H=√p²+b²
Here p is perpendicular and b is base
H=√ 3²+ 4²= 5
Now
SinA = p/h = 3/5
CosA= b/h = 4/5
TanA =p/b = 3/4
And reverse the ratio for getting Cosec sec and cot
Hope this helps u
H=√p²+b²
Here p is perpendicular and b is base
H=√ 3²+ 4²= 5
Now
SinA = p/h = 3/5
CosA= b/h = 4/5
TanA =p/b = 3/4
And reverse the ratio for getting Cosec sec and cot
Hope this helps u
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