Question

In a beam of 6 m span with one end hinged and other on roller if 30 kN-m
moment is acting at 2 m from support A, then the reaction at A is​

Answer 1

Given : span ($l$) = 6 m

      Moment @ 2 m from support A = ±30 KN.m

(± is because direction of the moment applied is not mentioned)

Let Ra and Rb be the reactions at support A & B.

Applying equation of equilibrium, ∑M = 0

taking moment about point B,

Rax6 ± 30 = 0

⇒ Ra  = ± 30/6 = ± 5N

∴ Ra = -5N ( if moment 30KN.m applied is clock-wise)

            or

Ra = +5KN.m ( if moment 30KN.m applied is anti-clockwise)

HOPE THIS HELPS YOU !!   : )