in a box there are 4 red 3 blue 5 green balls one ball is picked up randomly what is the probability that it is neither red or green
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there is a total of 12 balls in the box
4 red 3 blue and 5 green
if they picked up a random ball the probability that it is red or green is 9/12
but both 9 and 12 are divisible by 3
so your final answered should be 3/4
hope this helps :)
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Answer:-
• Given:-
Number of red balls = 4
Number of green balls = 5
Number of blue balls = 7
_____Find_____
The probability that it is neither red nor blue.
• Solution:-
Total number of balls in the bag = 4 + 5 + 7 → 16
Probability= No.ofexperiments
Totalno.ofoutcomes
• Probability of red ball = 4/16 = 1/4
• Probability of green ball = 5/16 = 5/16
• Probability of blue ball = 7/16= 7/16
Event that the ball is neither red nor blue = Event that the ball will be green
→ Probability = 5/16
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