Math, asked by bandalaramanand, 1 year ago

in a certain magazine 11/27 consists of advertisements and 1/3 of illustrations what fraction is readable matter

Answers

Answered by santy2
26

Answer:

7/27

Step-by-step explanation:

This is a question on fractions.

It is about addition and subtraction of fractions.

The total fraction used in advertisements and illustrations is given as :

= 11/27 + 1/3 = 20/27

The remaining part of the magazine is the readable matter.

We therefore needs to get what remains.

The remainder is given as :

1 - 20/27 = 27/27 - 20/27 = 7/27

7/27 is the readable part of the magazine.

Answered by amitnrw
26

Answer:

readable matter = 7/27

Step-by-step explanation:

in a certain magazine 11/27 consists of advertisements and 1/3 of illustrations what fraction is readable matter

advertisements in magazine = 11/27

Illustrations in magazine = 1/3

Total content of magazine = 1

Readable matter = Total content - advertisements - illustrations

=> Readable matter = 1 - 11/27 - 1/3

=>Readable matter = (1/27)(27 - 11 - 9)

= 7/27

readable matter = 7/27

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