In a certain region of space, electric field is along the Z-direction
throughout. The magnitude of electric field is, however, not constant
but increases uniformly along the positive z-direction, at the rate of
105NC- per metre. What are the force and torque experienced by a
system having a total dipole moment equal to 107 Cm in the negative
z-direction ?
class 12th physics question....plz don't write useless things
Answers
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Answer:
swampu and densed region well nt developed
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Explanation:
- Dipole moment of the system, p = q×dl = −10^−7 Cm
- Rate of increase of electric field per unit length,
dE/dl = 10^5 NC^−1
- Force (F) experienced by the system is given by the relation,
F = qE
F = (q × dl) × (dE/dl)
=p × (dE/dl)
=10^−7 × 10^−5
=−10^−2 N
- The force is −10−2N in the negative z-direction i.e., opposite to the direction of electric field. Hence, the angle between electric field and dipole moment is 180°.
- Torque (τ) is given by the relation,
T = pEsin180° = 0
- Therefore, the torque experienced by the system is zero and the force is −10^−2 N
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