In a certain town, male and female each form 50 per cent of the population. It is known that 20
per cent of the males and 5 per cent of the females are unemployed. A research student
studying the employment situation selects an unemployed person at random. What is the
probability that the person so selected is:
(a) male? (b) female?
Answers
Answer:
male is the answer ✌️✌️✌️✌️
Answer:
(a) male P(E) = 8/19
(b) female P(E) = 9/19
Step-by-step explanation:
Given that ,
In a certain town , male and female each form 50 percent of the population. It is known that 20 percent of the males and 5 percent of the females are unemployed.
A research students studying the employment situation selects an unemployed person at random.
To find the probability that the person so selected is,
(a) male (b) female
So,
Let the total population of town = 100
As per question ,
male 50% = 100/2 = 50
female 50% = 100/2 = 50
unemployed male is 20% = 20% of 50
= 10
unemployed female is 5% = 5% of 50
= 2.5 ( it is not possible , so i take 10%)
unemployed female is 10% = 10% of 50
= 5
Total number of employed male and feamle,
employed male = ( total male - unemployed male)
= ( 50 - 10 )
= 40
employed female = ( total female - unemployed female)
= ( 50 - 5 )
= 45
The probability of selected male -
P(E) = employed male / total employed candidates
= 40 / 95
= 8/19
The probability of selected female-
P(E) = employed female / total employed candidates
= 45 / 95
= 9/19
THANKS.
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