In a Circle of radius 6 cm, a chord of length 10 cm makes an angle of 110degree at the centre of circle. Find the:-
The circumference of the circle
the area of thr circle
The length of the arc AB
the area of th sector OAB.
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Length of the chord of circle = 10cm (Given)
Radius of circle = r = 6 cm (Given)
Angle at the centre of the circle = 110° (Given)
1. Circumference of a circle
= C = 2πr
C = 2 × 22/7 × 6
C = 264/7
C = 37.71 cm
Thus, the circumference of a circle = 37.71 cm
2. Area of a circle,
A = πr²
A = 22/7 × 6²
A = 22/7 × 36
A = 113.1 cm²
Thus, area of a circle = 113.1 cm²
3. Length of an arc
l = (θ/360) × 2πr
l = (110/360) × 2 × 22/7 × 6
l = 11/36 × 44/7 ×6
l = 484/ 6×7 = 484/42
l = 11.52 cm
Thus, the length of an arc AB is 11.52 cm
4. Area of the sector of a circle
AOB = (θ/360) × πr²
= (110/360) × 22/7 ×6²
= 11/36 × 22/7 × 36
= (11 × 22 ) /7
= 34.5 cm²
Thus, the area of sector of a Circle ,AOB is 34.5 cm²
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