Question

in a circle with center o the secant is a:pq b:xy c:qr d:AB​

Answer 1

Step-by-step explanation:

refer to the attachment

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Answer 2

Wh

PQ is a tangent at a point C to a circle with centre O. if AB is a diameter and ∠CAB=30

∘

, find ∠PCA.

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Video Explanation

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Answer

Given: PQ is a tangent. AB is a diameter, ∠CAB=30

o

To find: ∠PCA=?

In ΔAOC,

∠CAB=∠OCA (Angles opposite to equal sides are equal)

So, ∠CAB=30

o

=∠OCA

Since OC⊥PQ (Tangent is perpendicular to the radius at point of contact)

∠PCO=90

o

∠OCA+∠PCA=90

o

30

o

+∠PCA=90

o

∠PCA=90

o

−30

o

Therefore, ∠PCA=60

o

solution

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Two secants PAB and PCD are drawn