Question

In a circle with centre O , chord PQ is of length 16 cm , segment OB is perpendicular to chord PQ then find l( QB)

Answer 1

Answer:

We know that ,

The perpendicular from the centre of a

circle to a chord bisects the chord .

It is given that ,

PQ = 16cm

OB perpendicular to PQ

So,

PB = QB = PQ/2

Therefore,

PB = QB = 16/2 = 8cm

l( QB) = 8cm

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