In a class of 250 sttudents, 75.8% took french n 49.4% took latin. How many students took both french n latin??
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15
let total no of student be 100%
(75.8% + 49.4 %)=125.2 %
so , student % took both sub = (125.2-100)%=25.2%
no of student = 250×25.2%=63
(75.8% + 49.4 %)=125.2 %
so , student % took both sub = (125.2-100)%=25.2%
no of student = 250×25.2%=63
ankit6390:
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wlcm
wrong -36+32=68, right - 54+34=88, error = 88-68=20 and 20 error fr 100 number , so each no. has error = 0.2 so new avg = 40-0.2=39.8
heyy srry srry , new avg is 40+0.2=40.2
srry glti s type ho gya
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Answered by
1
if given that every student has taken at least one subject then...
percentage of students who have taken both French and Latin are =(75.8-49.4)%=26.4%
so number of those students are=26.4% of 250
=(26.4/100)×250
=(264/1000)×250
=264/4
=66 students
percentage of students who have taken both French and Latin are =(75.8-49.4)%=26.4%
so number of those students are=26.4% of 250
=(26.4/100)×250
=(264/1000)×250
=264/4
=66 students
Thanks!! But answer is 63 in my test series
hmmm sorry... my answer is incorrect...
No problem...You atleast tried!! Goodluck
: )
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