Question

In a class of 50 students, 20 students play badminton and 32 students play Volleyball. If 10 students play both, how many students play aneither of The sports and b) either sports?
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Answer 1

Answer:

Step-by-step explanation:

n(u)=50

n(b)=20

n(v)=32

n(b intersection v)=10

n(b union v)=n(b)+n(v)-n(b intersection v)

                   =20+32-10

                   =42

n(b union v)complement=n(u)-n(b union v)

                                        =50-42=8

no(b)=20-10=10

no(v)=32-10=22