Question

In a class of 60 students , 40% of the students passed in reasoning, 5% of the students failed in quants and reasoning, and 20% of the students passed in both the subjects. find the number of student passed only in quants?

Answer 1

Answer:

Step-by-step explanation:

Total students failed = 5% of 60

= 5/100 * 60 = 3

Total students passed in both = 20% of 60 = 20/100 * 60 = 12

Total students passed in reasoning = 40% of 60 = 40/100 * 60 = 24

Students passed in reasoning only = 24 - 12 = 12

Students passed in quants = 60 - 12 - 12 - 3 =33

Answer 2

Concept Introduction:-

It could take the shape of a word or a number representation of the quantity's arithmetic value.

Given Information:-

We have been given that In a class of $60$ students, $40\%$ of the students passed in reasoning, $5\%$ of the students failed in quants and reasoning, and $20\%$ of the students passed in both the subjects.

To Find:-

We have to find that the number of student passed only in quants.

Solution:-

According to the problem

Total students $=60$

Failed in both $=5 \%$ of $60=3$

Passed in both $=20 \%$ of $60=12$

Passed in reasoning $=50 \%$ of $60=24$

Those passed only in reasoning $=24-12=12$ students.

Passed only in Quants $=60-(12+12+3)=33$

Final Answer:-

The correct answer is $33$ passed only in quants.

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