Physics, asked by anaitasahoo2007, 6 months ago

In a cricket match, a cricketer tries to play hook shot but the ball takes the edge of his bat and

rises vertically upwards with an initial velocity of 30 m/s. The fielder settles himself under the

ball and takes the catch comfortably after n seconds since the batsman had edged the ball.

What would be the value of n ?

(Take g = 10 m/s2

and neglect any air resistance

***those who will answer I will mark it BRAINLIEST***​

Answers

Answered by avni3591
2

Answer:

In a cricket match, a batsman hits the ball in air. A fielder, originally standing at a distance of 12 m due east of the batsman, starts running 0.6 s after the ball is hits. He runs towards north at a constant speed of 5m/s and just manages to catch the ball 2.4 s after he starts running. Assume that the ball was hit and caught at the same height and take g=10m/s2g=10m/s2 Find the speed at which the ball left the bat and the angle that its velocity made with the vertical.

Explanation:

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