Biology, asked by kiransharma060ov55g9, 1 year ago

In a cross between round yellow seeds [RRYY] and wrinkled green seeds [rryy]of pea plant, what is the ratio of plants obtained in F2 generation?

Answers

Answered by Rahul1905
122
phenotypic ratio 9 : 3 : 3 : 1
genotypic ratio 1 : 2 : 1 : 2 : 4 : 2 : 1 : 2 : 1

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Answered by StaceeLichtenstein
114

Answer: The phenotypic ratio of plants in F2 generation is -

9:3:3:1 ( Round yellow: Round green: Wrinkled yellow: Wrinkled green).

The genotypic ratio of the plants in F2 generation is-

1:2:1:2:4:2:1:2:1 ( RRYY: RRYy: RRyy: RrYY: RrYy: Rryy: rrYY: rrYy: rryy).

Round yellow is a dominant trait over wrinkled green. When the given parental plants (with genotype RRYY and rryy) are crossed, they will produce RrYy (Round yellow offsprings) in the F1 generation. Now parents with genotype RrYy will interbreed and produce phenotypes in the ratio 9:3:3:1 and genotypes in the ratio 1:2:1:2:4:2:1:2:1 in the F2 generation.

Refer punnett square.  

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