Question

in a family there are three children's assuming that the chances of a child being a male or female
find the probability that

I) there is one girl in a family

ii) there is no male child in the family

iii)there is at least one male in the family


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Answer 1

The complement of at least one boy is all three girls

So, P(P( at least one boy)=1−P(GGG))=1−P(GGG)

=1−(12)3=1−(12)3

This is the de facto way of solving problems of Probability of at least one in case of Binomial Distribution like tossing a coin etc.

Answer 2

#Boy= (B) and Girl=(G)

#Possible outcomes =(BBB),(BBG), (BGB), (GBB), (BGG), (GBG), (GGB), (GGG).

#(i) P(E) =Favorable outcomes /Possible outcomes

= 3/8

#(ii) P(E) = 1/8

#(iii) P(E) =7/8
HOPE IT WILL HELP YOU!!!