Question

In a figure, it states that DB Perpendicular BC ; DE Perpendicular AB ; AC Perpendicular BC. Prove that BE/DE = AC/BC.Plzz urgent.!!

Answer 1

in triangle deb and acb,
angle DBE=ANGLE ABC (COMMON)
ANGLE DEB =ANGLE ACB(EACH 90 )
THEREFORE  TRI DEB AND ACB ARE SIMILAR (BY AA RULE)
BE/BC=AC/DE
THEREFORE, BE/DE=AC/BC

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