Question

In a fraction if numerator is increased by 2 and denominator is increased by 3 it becomes 3/4 and if numerator is decreased by 3 and denominator is decreased by 6 it becomes 4/3. Find the sum of the numerator and denominator

Answer 1

Answer

Let the fraction be -x/y

As per the given statements,

y−4

x+2

=2

⇒x+2=2y−8

⇒x−2y=−10 --- (1)

Also,

y+2

x−1=1/3

⇒3x−3=y+2

⇒3x−y=5 --- (2)

Multiplying eqn (2) by 2 and subtracting eqn (1) from it, we get

2(3x−y)−(x−2y)=2(5)−(−10)

⇒5x=20

⇒x=4

Substituting this value of x in eqn (2), we get

3(4)−y=5

⇒y=12−5=7

∴x=4;y=7

So, x+y=4+7=11

Answer 2

Answer:

x+y= 4+7 =11 this is your answer