Question

In a geometric progression second term is 6 in and fifth term is 48 find the 10 term

Answer 1

Answer:

Step-by-step explanation:

Given 2nd term is 6.

So, by A.P. formula, a+(n-1)d=term.

Putting the values,

a+(2-1)d=6

Therefore a+d=6 ----(1)

Also, a+(5-1)d=48

Therefore a+4d=48 ----(2)

Subtracting (1) by (2), we get

3d=42, d=14

Now using the value of d in (1) we get

a=(-8).

The A.P. becomes -8, 6, 20, 34......

Now we have to find the 10th term,

here, a=-8

d=14

n=10

Using values,

-8+(10-1)×14 ==> -8+9×14 ==> -8+126 ==> 118.

Therefore the 10th term of this A.P. is 118.

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