in a gp, if the first term is 3/4, common ratio is 2 and the last term is 389, find the number of terms
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general term of an gp is given by an=ar^(n-1)
(3/4)(2)^(n-1)=389
2^(n-1)=389*4/3
solve
(3/4)(2)^(n-1)=389
2^(n-1)=389*4/3
solve
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