In a house 11 bulbs are connected in parallel.each bulb takes a current of 0.1A from 220 V power supply.calculate tbe rssistance of all tbe bulbs and curremt in the leads.
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Answer:
Let R' be the resistance for 1 bulb
R'= V/I
R'= 220/0.1
R'= 2200Ω
Resistance for 11 bulbs, R= 11*1/R'
= 11*1/2200
= 11/2200
= 200Ω
Total Current, I'= 11*I
= 1.1A
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