Physics, asked by Nairnad8harunP, 1 year ago

in a house 4 bulbs of 50W each are used for 5 hours a day and two 70 W fans each fan used 10 hours a day. calculate the unit consumed in a month of 30 days


YadavShashi: it is question of calss 9th
YadavShashi: sa2 paper n

Answers

Answered by VinayRajKumar
1
As you said , if a house have 4bulbs which consume 50w per hour and used for 5 hours, then 4*50W=200W
And 2 fans of 70W*10 = 700W
Units consumed in 30 days
=(200*5+700*10)30/1000
=(1000+7000)30/1000
=8000*30/1000
=240000/1000
=240 KWH

Subhikshamurari: There is a mistake in your answer please edit it.
Subhikshamurari: it is 700*2 & not 700*10
VinayRajKumar: Thanks for the correction.
Answered by harisreeps
0

Answer:

In a house, 4 bulbs of 50W each are used for 5 hours a day and two 70W each, fans are used 10 hours a day, the units consumed in a month of 30 days is 72KW

Explanation:

The number of bulbs  =4

power used by one tube light =50W

working time of tube light in a day =5hrs

total power consumption of tube light in a month =30*5*50*4=30000W

The number of fans =2

power used by one fan =70W

working time of a fan in a day =10hrs

total power consumption of the fan  =30*10*70*2=42000W

so the total power consumption of the home =30000+42000=72000W=72KW

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