Physics, asked by rajgopal1848, 10 months ago

In a house the electric devices operated in the following way 3 bulb of 40 watt for 3 hour 2 fans of 60 watt for 4 hours .calculate the energy consumed by them in units for the month of June also .calculate bill if rate is 4.15 per unit.

Answers

Answered by nidhigupta28935
0

Energy consumed by 3bulbs= 3×40×3

=360Wh

Energy consumed by fans= 2×60×4

=480Wh

Total energy consumed by fans and bulbs= 360+480

=840Wh

=0.84 KWh or 0.84 unit

Total cost in 30 days= 30 × 0.84 ×4.15

1145.8 rupees

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