In a hydro electric power station, 1000 * 10 to the power 3 kg water falls through a height of 51 m in one second . Calculate (i) work done by the falling water and (ii) power generated under ideal conditions . (g=10ms-1)
Answers
Answered by
4
Answer:(i)Work done: 51000*10^4J (ii) Power generated : 51000*10^4 Watt
Explanation:
Initial potential energy possessed by water :mass*g*height
= 1000*10^3 * 10 * 51 J
decrease in potential energy = increase in kinetic energy
energy transformation: Potential energy->Kinetic energy->Electrical energy
Therefore,work done by Water in one second = 51000*10^4 J
power = work done/time
= 51000*10^4/1 Watt
=51000*10^4 Watt
Similar questions