Physics, asked by mike6891, 9 months ago

in a large room a person receives direct sound wave from a source 120m away from him. He also receive wave from same source which reaches him after being reflected from 25m high ceiling at a point midway between them . two waves interfere constructively for wavelength of (in meter)

Answers

Answered by rejibala21
0

Answer:

20, 20/3, 20/5 etc

Explanation:

Let

S

be source of sound and Pthe person or listner. The waves from

S

reach point Pdirectly following the path SMPand being reflected from the ceiling at point

A

following the path SAP.

M

is mid-point ofSP(i.e.

SM=MP)

and

∠SMA=

90 o

Path difference between waves

Δx=SAP−SMP

We have

SAP=SA+AP=2(SA)

=

2

[

(SM) 2

+

(MA) 2

]

− − − − − − − − − − − − − − √=2

(

60 2

+

25 2

)

−−−−−

−−√=130

m

∴Path difference = SAP ? SMP =130−120=10m Path difference due to reflection from ceiling =

λ

2

∴ Effective path difference Dx =

10+

λ

2

For constructive interference Δx=10+

λ

2

=nλ⇒(2n−1)

λ

2

=10(n=1,2,3....)∴Wavelength

λ=

2×10

(2n−1) =

20

2n−1

. The possible wavelength are l=

20,

20

3

,

20

5

,

20

7

,

20

9

,

?..

=

20

m

,6.67m,4m,2.85m,2.22

m,

Hope it will help you

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