In a leap year find the probablity that there are 53 tuesdays in year
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In a leap year find the probability that there are 53 Tuesday in year
There are total 366 days in a leap year. [ 52 weeks ( 7 days ) and 2 days ]
There are 7 days in a week. Then the probability that the remaining is a Tuesday
P(E) = 2/7
There are total 366 days in a leap year. [ 52 weeks ( 7 days ) and 2 days ]
There are 7 days in a week. Then the probability that the remaining is a Tuesday
P(E) = 2/7
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There are 52 weeks in a leap year with two days left day
52*7=364 364+2=366
So these two days can be Monday Tuesday or Tuesday Wednesday or Wednesday Thursday and so on
Total outcome =7
Favorable one=2
So probability is =favourable /total
P(E) =2/7
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