Question

In a morning walk a man, a woman and a child step off together. Their steps measure 90 cm, 80 cm and 60 cm. What is the minimum distance each should walk to cover the distance in complete steps?

Answer 1

in a morning walk a man ,a woman and a child setp off together.
length of men's step = 90cm
length of woman's step = 80cm
length of child's step = 60 cm

minimum distance each should walk to cover the distance in complete steps = LCM of {90, 80, 60}
= 720 cm

hence, minimum distance = 7.2 m

Answer 2

Given Man's measure = 90 cm.

Given women's measure = 80 cm.

Given Child's measure = 60 cm.

Therefore,

The minimum distance each should walk is the LCM of 90,80,60.

= > Prime factorization of 90 = 2 * 3 * 3 * 5

= > Prime factorization of 80 = 2 * 2 * 2 * 2 * 5

= > Prime factorization of 60 = 2 * 2 * 3 * 5

LCM(90,80,60) = 2 * 2 * 2 * 2 * 3 * 3 * 5

= > 720.

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Therefore,

Minimum distance = 720 cm

= > 0.0072km.

Hope this helps!